How to open a directory?

[maxic]

Probably LUA a script to open a directory and to receive the list of files?

[myles]

Something like this will allow the user to select from a list of files:

Code: Select all

	local infilename = LM.GUI.OpenFile("Select Input File")
	if (infilename == "") then
		return
	end

	local f = io.open(infilename, "r")

Regards, Myles.

[maxic]

The list of files of a directory is necessary

As in other programs:

DIR

.
..
file1
file2
file3
..........
file(n)

I it need to import sequence of raster images

[Lost Marble]

The Lua interface can't give you a directory listing, but consider this:

1. Bring up a file dialog and let the user pick the first file.
2. The user picks "image_001.jpg"
3. The Lua script then starts loading "image_002.jpg" "image_003.jpg" "image_004.jpg" etc.

Assuming the images are numbered in sequence, Lua can just open them one at a time. Instead of a directory listing, Lua can guess the next file's name based on the last one and just has to check whether each file exists or not.

[maxic]

Thanks for good idea!